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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Jan 2008 16:40:22 IST
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C(s) + 1/2 O2(g) ------> CO(g) ; Delta rH0 = -110KJ C(s) + H2O (g) -------> CO(g) + H2 (g) ; Delta rH0 = 132 KJ Composition of steam and O2 when it passed over coke keeping temperature 1273K will be- A-1:2 B-5:3 C-4:5 D-1:1 Please tell the answer along with explanation.
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18 Jan 2008 18:21:53 IST
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Sumbody help pleeeeeeeeeeez.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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Back to goiit, this time with Baby Veerappan. :D |
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18 Jan 2008 18:36:43 IST
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for the first reaction ds is negative therefore
dG=-110+ dS * 1273
dS is negative so the above expression
here G is sure to be positive because of the high temperature
hence i dont think the reaction will occur
same goes for the second reaction also
so the ratio should be 1:1
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18 Jan 2008 18:40:12 IST
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i think the answer is 5:3 bcoz for the first reaction entropy is -ve, so it is spontaneous, so oxygen is readily used where as for the second reaction entropy is +ve so it is not readily used so it will remain in more amount
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18 Jan 2008 18:42:38 IST
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@suns_uday
-ve entropy does not imply that the reaction is spontaneous
it is the change in gibbs energy that indicates whether or not a reaction is spontaneous
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18 Jan 2008 18:47:06 IST
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uday is correct.
The ans is 5:3.
But please explain. I cudn't understand the reason U hav given in ur last post.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
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18 Jan 2008 18:55:20 IST
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sorry man
made a blunder
in the first reaction there is i mol of gas in the product
and half a mol of gas in the reactant side
so dS is +ve
so dG is sure to be negative and the reaction occurs
for the second reaction also dS is positive
but there dH is +ve
so the probability that dG is negative is lesser than the previous case
so the second reaction occurs to a lesser extent than the first
so the amount of steam must be greater than amount of oxygen
hence 5:3
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18 Jan 2008 19:01:30 IST
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oops sorry i forgot the factors wether it is entropy or gibbs energy sorry till now i got confused b/w them now its cleared thank u
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18 Jan 2008 19:01:38 IST
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Thanx madman,
can u plz explain me why in the first reaction dS>0?
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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18 Jan 2008 19:03:49 IST
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in the first reaction dH is +ve and T is also +ve and dS=dH/T
so dS=-ve /+ve =-ve
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18 Jan 2008 19:05:25 IST
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greater the amount of gas greater the entropy
as entropy is the amount of disorderness of a system
there is 1 mol of gas in the product but only half a mol in the reactant side
so the product side has greater amount of disorderness
hence dS is +ve
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18 Jan 2008 19:07:01 IST
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Thanx.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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Back to goiit, this time with Baby Veerappan. :D |
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