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Forum Index -> Physical Chemistry like the article? email it to a friend.  
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bupi (0)

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cal the heat of rxn at a constant pressure and that at a constant  volume for the combustion of two moles of liq benzene at 25*C
    
smriti.mathur (437)

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Combustion equation of benzene for 2 moles-
2 C6H6 (l) + 15 O2 (g) 12 CO2 (g) +6 H2O , H= ?
H = (Enthalpy of products - Enthalpy of reactants)
=(12* del H(f) CO2(g) +6* del H(f) H2O)   -  (2* del H(f) C6H6(l) + 0)
=(12*  -94.3    + 6*   -68.4)   -  (2*   +11.7)
=    -1565.4 K. Cal
H= qp
E= qv
H= E +nRT
-1565.4= E  +(12  -  15)0.002 * 298
E=   -1563.6
 

Lecturar, Organic Chemistry
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