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2 Jun 2012 20:21:27 IST

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volumetric calculations

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What volume of N/2 and N/10 H2SO4(sulphuric acid) must be mixed to prepare 5 litres of N/5 H2SO4??

Pls explain and answer....

Comments (3)

Uppinder Chugh

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3 Jun 2012 10:17:31 IST

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Let volume of N/2 solution of H₂SO₄ be x litre, then volume of N/10 soluton of H₂SO₄ be (5 - x) litre (As total volume of required is 5 litre. Now, we have to equalize the gram equivalents of the give solutions and required solution, thus we get

Solving for x we get, x = 1.25 litre.

Therefore, vol. of N/2 solutions is 1.25 litre and vol. of N/10 solution will be 5-1.25 = 3.75 litre. Cheers.

ananya sharma

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3 Jun 2012 11:35:22 IST

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thanx a lot...u r a genius...!!!

Krishna Gopal Singh

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9 Jun 2012 17:21:21 IST

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Let they are x and 5-x ltrs . So x/2 + (5-x)/10 = 5*1/5 . By solving this we get .4x = 0.5 or 1.25 L of N/2 + 3.75 L of N/10 H2SO4 will give 5 L of N/5 H2SO4

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