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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Aug 2007 16:45:50 IST
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A mixture of FeSO4 and FeC2O4 required 250 ml of 0.1 M acidified KMnO4 for oxidation. If molar ratio of FeSO4 and FeC2O4 in the mixture is 2:1, find masses of them in mixture.
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This is just da beginning .....
Ankur |
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15 Dec 2007 16:59:28 IST
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Fe2+ -> Fe3+ + 1e let moles be 2x, n1=1
FeC2O4 -> Fe3+ + 2CO2 + 3e ; moles be x(using given data), n2=3
KMnO4 <=> Mn7+
in acidic medium
Mn7+ + 5e => Mn2+ ; thus n3=5
N3V3 = n3*m3*v3 = 2x*n1 + x*n2 [using equivalent concept]
solving gives x = 0.025moles.
mass of FeSO4 = 2x*152 = 3.8gm
mass of FeC2O4 = x*144 = 3.6gm
plz rate if helpful.
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