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Physical Chemistry

Cool goIITian

Joined:	31 Jul 2009
Post:	61

28 Nov 2011 21:53:04 IST

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which one of the follwoing has delta S not greater than 0

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a- Cao+ Co2 (g) ----CaCo3

b- Nacl (aq) --------Nacl (s)

c- NaNo3(s) ---------Na+ + No3-

d- N2g+3h2 ----------2Nh3

Comments (3)

RISHABH BAJPAI

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Joined: 3 Nov 2011

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29 Nov 2011 18:45:55 IST

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delta S ,i.e. change in entropy or randomness...you must know that entropy in gases is more than liquids and in liquids is more than gases....if on both sides reactants and products are in same state consider delta S +ve i.e increasing entropy on that side which has more no. of gaseoues products......

in a) CaO(s) + CO2(g) ---> CaCO3(s) therefore delta S is -ve

in b) NaCl(aq) ---> NaCl(s) therefore delta S is -ve

in c) NaNO3(s) ---> Na+ + NO3- therefore delta S is +ve (since ions are free to move therefore randomness increasing)

in d) N2(g) + 3H2(g) ---> 2NH3(g) therefore delta S is -ve (since no. of moles on product side is lesser)....

PLS RATE IF SATISFIED......

Vikram Saxena

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Posts: 4025

6 May 2012 14:07:41 IST

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IN third equation ions are forming thereby increasing the randomness hence delta s will be +ve

akshit

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Joined: 11 May 2012

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11 May 2012 14:36:17 IST

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