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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Mar 2008 19:34:14 IST
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why in an adiabatic expansion,w=0
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29 Mar 2008 20:20:11 IST
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u are wrong man!!!!!!!!!!! work done is not zero.......
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29 Mar 2008 22:16:45 IST
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in adiabatic process work done is not =0 dQ=0 since dt=0 since adiabatic processoccurs in an isolated system hence dT=0 i.e;dU=nCvdT
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29 Mar 2008 22:38:57 IST
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in adaibatic process d system is isolated one thus Q=0 thus delE=delQ+W thus enegy =work done  |
don't walk as if u rule d world
walk as if u dont care who rules d world
-this is knw as attitude
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30 Mar 2008 08:29:52 IST
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sorry ,i meant the case of 1 mole of ideal gas
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30 Mar 2008 08:33:58 IST
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work done ad. is no means zero use ; w= nr/y-1 [ t1 - t2 ] r = gas const. y= gamma n = no. of moles plz rate if useful cheers
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