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Blazing goIITian

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1 Feb 2010 23:06:07 IST

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Why is delta G,G(std),=0 at eq?

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Why is delta G,G(std),=0 at eq?

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Nimisha Radhakrishnan

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Joined: 5 Jan 2010

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4 Feb 2010 14:18:44 IST

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It is so because at equilibrium the reaction is taking place in both directions, forward and reverse. When the direction of a reaction is reversed, the thermodynamic values also change sign. So at equilibrium the delta G is the addition of the forward direction reaction delta G to the reverse direction reaction delta G, so

^G = +G kJ + (-G kJ) = 0.

akansha

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Joined: 14 Mar 2009

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5 Feb 2010 08:30:53 IST

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at equlibrium their is no energy barrier b/t product and reactant sothe change in randomness is equal in magnitude but opp. in sign thus cancels each other

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