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Thermal Physics

Blazing goIITian

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29 Mar 2012 15:15:33 IST

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317

heat

Engineering Entrance , Medical Entrance , AIPMT , JEE Main , AIIMS , JEE Advanced , Physics , Thermal Physics

A cuboid ABCDEFGH is anisotropic with

ax = 1×10^-5 /°C, ay= 2 × 10^-5 /°C, az = 3 × 10^-5/°C. Coefficient of superficial expansion of faces can be

Comments (11)

pooja garg

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29 Mar 2012 15:39:01 IST

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three cefficients are there 1.ax +ay2.ay + az3.az + ax

Gargee Mehta

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29 Mar 2012 15:54:48 IST

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Now your options

(A)bABCD = 5 × 10^-5 /°C (B) bBCGH = 4 × 10^-5 /°C

pooja garg

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29 Mar 2012 16:00:33 IST

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option c

Gargee Mehta

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29 Mar 2012 18:49:28 IST

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hey pooja c is the ans how did you get it?

Tarun Garg

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29 Mar 2012 18:54:57 IST

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Yar koi in chapter ko smja do kuki ye chapter m m bilku duffor hu>>sound wave,elasticity and expansion pls pls

Gargee Mehta

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30 Mar 2012 12:42:22 IST

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anyone?

santanu sinha

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30 Mar 2012 12:46:12 IST

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B and D..

Gargee Mehta

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30 Mar 2012 12:52:42 IST

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hey c is the ans.. tell me your approach..

Tarun Garg

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30 Mar 2012 13:56:04 IST

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hey same method for anisotreopic solid coe. of areal or superficial expansion through one face=sum of linear expansion of its dimension ............now for cdeh dimension are x and y component since z is constant for it so superficial expansion through it will be ax+ay=3*10^-5 c^-1

Tarun Garg

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30 Mar 2012 13:57:13 IST

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how many i am waiting 4 days i got the answer and tell them method but they dont like my post lets see whwt u do

santanu sinha

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30 Mar 2012 14:04:22 IST

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take a rectangle a by b.

for change in temp del T,the linear expansions be p and q along a and b..

A=ab.. change in area be del A

try to draw a picture yourself..its more convenient

del A= aq+bp+pq (ap=del a,bq=del b)

so del A=ab(p+q).del T pq is neglected as it is negligible..

del A/ A(del T)= p+q which is the coefficient of superficial expansion..

here p=10^-5,q=2*10^-5

adding we get C

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