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Thermal Physics

Blazing goIITian

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1 Mar 2009 21:00:30 IST

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JPS

Blazing goIITian

Joined: 21 Nov 2008

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1 Mar 2009 21:02:19 IST

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An insulated container has 5 moles of an ideal diatomic gas at temperature T. When Q heat is added to the gas, 3 moles of the gas are dissociated into atoms, (the temperature remaining same) then [R is gas constant] a. Q = RT b. Q = 1.5 RT c. Q = 2 RT d. Q = 2.5 RT

JPS

Blazing goIITian

Joined: 21 Nov 2008

Posts: 1020

3 Mar 2009 12:25:21 IST

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hey anyone answer this.......

JPS

Blazing goIITian

Joined: 21 Nov 2008

Posts: 1020

4 Mar 2009 10:35:01 IST

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can noone ans. this????????

sajal kumar

Cool goIITian

Joined: 26 Dec 2008

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4 Mar 2009 10:57:39 IST

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so when we add Q amount of heat 3 moles of diaatomic breaks to monoatomic...so we have 6 moles monoatomic gas....so total dU= finalU- initial U....... = (6*3/2 RT + 2*5/2 RT ) - 5*5/2 RT = 14RT - 12.5 RT = 1.5 RT....

so the answer is b, 1.5 RT.... got it...it's a simple problem..

JPS

Blazing goIITian

Joined: 21 Nov 2008

Posts: 1020

4 Mar 2009 12:52:17 IST

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man dats so simple.....i must be a fool to ask it

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