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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: A tricky question...
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prateek.agarwal (307)

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Its a multiple correct question...
The answers are (A) & (B)

    
KAB (1669)

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root(1-sinA)=sin(A/2)-cos(A/2) when sin(A/2)>cos(A/2)
 
When A/2 lies in 1st quadrant and pi/4<A/2<pi/2 ,sin(A/2)>cos(A/2)
So A/2-pi/4 lies in 1st quadrant
 
When A/2 lies in 2nd quadrant,A/2-pi/4 may lie in 2nd or 1st quadrant.
When A/2 lies in 3rd quadrant sin(A/2) and cos(A/2) both are negative.
Also when pi<A/2<5pi/4 sin(A/2)>cos(A/2)
So  3pi/4<A/2-pi/4<pi which is in 2nd quadrant.
 
So the correct answers are A) and B)

ADARSH
NITK Surathkal

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newarnav (218)

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Thats an Identity and valid for every real A

My name is Arnav.
AIR 7041 IIT-JEE 08 got nothin,
currently in MA NIT bhopal civil...
still ..Hoping we'll meet in IIT next year !
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