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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 May 2008 20:59:58 IST
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The rate constant for the decomposition of hydrocarbons is 2.418 x
10-5 /s at 546 K.If the energy of activation is 179.9 KJ/mol. Calculate
the value of pre-exponential factor
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7 May 2008 21:06:31 IST
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everythin is given and u just need to put those in this formula and get the value of "A".......
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7 May 2008 21:08:15 IST
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logK = -Ea/RT + log A
log 2.418 x 10 -5 = - 179.9 x 10 3 / 8.314 x 546 + log A
solve this, u'll get it
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Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
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7 May 2008 21:16:28 IST
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Have done this,but the answer is not coming,please solve
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7 May 2008 23:06:39 IST
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is it 1.023 X 10 ^35??
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Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
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