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Ask iit jee aieee pet cbse icse state board experts Expert Question: cosA+coaB+2cosC=2,then the sides of triangle ABC are in which progression
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jainsaurabh_3067 (0)

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cosA+coaB+2cosC=2,then the sides of triangle ABC are in which progression
    
deepesh28 (12)

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COSA +COSB=2(1-COSC)
COSA+B/2.COSA-B/2=2SIN^2C/2
SINC/2COSA-B/2=2SIN^2C/2
COSA-B/2=2SINC/2=2COSA+B/2
COSA/2.COSB/2+SINA/2SINB/2=2(COSA/2COSB/2-SINA/2SINB/2)
3SINA/2SINB/2=COSA/2COSB/2
TANA/2TANB/2=1/3
 
S-b.S-c/S.S-a  *S-c.S-a/S.S-b=1/3
S-c/S=1/3
3S-3c=S
2S=3c
a+b+c=3c
a+b=2c          hence sides r in AP
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puneet (3540)

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hii

very gud answer depeesh ..

i hope that every1 knw the answer now ..

cheers


Puneet Agrawal
IIT Delhi
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