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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: cosec - cot = q , then cosec = ________
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dhwanitmunshi (64)

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pls explain

if cosec - cot = q , then cosec = ________
(a) q +  1/q
(b) q - 1/q
(c) 1/2(q + 1/q)
(d) 2(q+1/q)

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nadeemoidu (1184)

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cosecA-cotA=q......................(1)

but , (cosecA-cotA)(cosecA+cotA) =1    [identity]

q(cosecA+cotA) =1

(cosecA+cotA) =1/q..................(2)


add (1) and (2) , we get the answer as (c)

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rabindra8 (73)

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use the formula  cosec2 -cot2 =1 and find out your required answer.
and i.e.  cosec = (q2 +1)/2q

I like to solve the tough problems, because nothing is tough.
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Aastha_faith (5)

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Cosec x =1/sin x
Cot x = cos x/sin x
 
Cosec x ? cot x = (1-cos x)/sin x
=>1-cos x = p sin x
 
P+1/p = (1-cos x)/ sin x + sin x /1-cos x
_____= [1+cos2 x ? 2 cos x + sin2 x] / (sin x) (1-cos x) ------------by taking LCM
_____= [1+1-2 cos x] / (sin x) (1-cos x) ----------since sin2 x+ cos2 x =1
_____= [2-2 cos x] / (sin x) (1-cos x) -------by taking ?2? common
_____= 2{1-cos x}/ (sin x) (1-cos x) -------- (1-cos x) in numerator & denominator
_____= 2 / sin x
_____= 2 cosec x
 
Therefore, cosec x = ½ (p + 1/p)
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Aastha_faith (5)

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Cosec x =1/sin x
Cot x = cos x/sin x
 
Cosec x ? cot x = (1-cos x)/sin x
=>1-cos x = p sin x
 
P+1/p = (1-cos x)/ sin x + sin x /1-cos x
_____= [1+cos2 x ? 2 cos x + sin2 x] / (sin x) (1-cos x) ------------by taking LCM
_____= [1+1-2 cos x] / (sin x) (1-cos x) ----------since sin2 x+ cos2 x =1
_____= [2-2 cos x] / (sin x) (1-cos x) -------by taking ?2? common
_____= 2{1-cos x}/ (sin x) (1-cos x) -------- (1-cos x) in numerator & denominator
_____= 2 / sin x
_____= 2 cosec x
 
Therefore, cosec x = ½ (p + 1/p)
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