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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Mar 2008 12:14:40 IST
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cot 4x( sin 5x + sin 3x ) = cotx (sin 5x - sin 3x ) prove
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use
sinC+ sin D= 2sin ((C+D)/2)cos( (C-D)/2)
sinC-sin D= 2sin ((C-D)/2)cos( (C+D)/2)
LHS reduces to
cot 4x( 2 sin 4x cos x)
=2cos 4x cos x
RHS=cot x( 2cos 4 x sin x)
=2 cos 4x cos x
so LHS=RHS proved
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1 Mar 2008 12:27:09 IST
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Thanks
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