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Trignometry

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30 Nov 2011 12:48:56 IST
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cot16cot44+cot44cot76-cot76cot16=
Mathematics

pl give me solution soon


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prahlad kumar sharma's Avatar

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Joined: 21 Jul 2010
Posts: 88
30 Nov 2011 19:03:27 IST
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                 cot16cot44+cot44cot76-cot76cot16

=    (cos16cos44)/(sin16sin44)  + (cos44cos76)/(sin44sin76) - (cos76cos16)/(sin76sin76)

=    (cos16cos44sin76 + cos44cos76sin16 - cos76cos16sin44) / (sin16sin44sin76)............i)

let me first simplify the numerator

    cos16cos44sin76 + cos44cos76sin16 - cos76cos16sin44

= cos44(sin76cos16+sin16cos76) - cos76cos16sin44

= cos44sin92 - cos76cos16sin44       {using sinAcosB+sinBcosA= son(A+B)}

= 2sin46cos46cos44 - cos76cos16sin44      { sin92=2sin46cos46}

= 2sin46sin44cos44 - cos76cos16sin44  

= sin44( 2sin46cos44 - cos76cos16)

= sin44[ (sin90 + sin2) - (cos92 + cos60)/2]          {using formulas of 2sinAcosB and 2cosAcosB resp.} 

= sin44[ (3/2-3cos92)/2]         {sin2= -cos92}

= 3sin44[(cos60-cos92)/2] 

= 3sin44sin16sin76    { since (cos60-cos92) = cos(76-16)-cos(76+16)= 2sin16sin76}

substituting this value in the place of numerator in i) we get

(3sin44sin16sin76)/(sin16sin44sin76)

= 3 ans.    __/\__

 

 

Manasi's Avatar

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Joined: 1 Dec 2006
Posts: 2108
11 Feb 2012 12:37:25 IST
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the question has been already solved by prahlad !!
thank u :)



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