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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Mar 2007 16:06:04 IST
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find general solution of 2(sinx - cos2x) - sin2x(1 + 2sinx) + 2cosx = 0
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There is no better feeling in this world than being a winner! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 15:50:03 IST
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come on experts...this must be easy for u guyz!
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There is no better feeling in this world than being a winner! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 19:29:20 IST
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Firstly......To Get Answers From Experts Post This Question In Expert Section......Secondly The Answer Is 0
I Did Not Solve This Sum ....... Whenever U have a sum on general solution always use 10 seconds and first check if the values 0,90 are satisfyin......i did that and 0 satisfies the equation........ ill will try to put up a logical proof
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 20:12:57 IST
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ya ok...thanks
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There is no better feeling in this world than being a winner! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 20:24:47 IST
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hey i got the solution 2(sinx- cos2x) - sin2x(1+2sinx) +2cosx=0 2(sinx - 1 +2sin2x) - 2sinxcosx(1+2sinx) +2cosx=0 2sin2x +sinx -1- sinx cosx -2sin2xcosx +cosx=0 2sin2x(1-cosx) +sinx(1-cosx) -(1-cosx)=0 implies 2sin2x + sinx -1=0 or 1-cosx=0 sinx = -1 or 1/2 cosx =1 sinx = sin(-pi/2) or sin(pi/6) cosx = cos 0 x = n(pi) +(-1) n(-pi/2) or n(pi) +(-1) n (pi/6) x= 2n(pi) x= {n(pi) +(-1) n(-pi/2)} U {n(pi) +(-1) n (pi/6)} U {2n(pi)} cheeeeeeeers plzzzzzzz gimme ur rates
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 20:30:36 IST
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excellent job vasanth!..take a salute
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There is no better feeling in this world than being a winner! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 23:50:29 IST
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thanx man
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2007 00:40:04 IST
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2sin2x + sinx -1=0 or 1-cosx=0 how did u get this step can u plzzzzzzz explain
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[bold]"everyone on earth has a treasure that awaits him, weva ur heart iz ull find ur treasure"[\bold]--from the alchemist by PAUL COELHO |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2007 00:43:01 IST
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2sin2x(1-cosx) + sinx(1-cosx) -1(1-cosx)=0 the aboveequation equates to zero if and only if 2sin2x + sinx -1=0 or 1-cosx=0 for better understanding 2sin2x(1-cosx) + sinx(1-cosx) -1(1-cosx)=0 can b written as (2sin2x + sinx -1)(1-cosx)=0 and hence the step 2sin2x + sinx -1=0 or 1-cosx=0 hope u got it dont 4get 2 rate me cheeeeeeers
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2007 01:15:11 IST
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plzzzzzzzzz ask if u r not clear
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2007 01:22:21 IST
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hey......u hav a gr8 mind vasanth...!!!!!
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surbhi mittal |
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