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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Oct 2007 17:48:24 IST
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3sin  + 5cos  =5 then value of 5sin  -3cos  = ?
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Woods are lovely dark and deep
But i have promises to keep
And miles to go before i sleep
And miles to go before i sleep
" HAVE A NICE DAY "
    
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Oct 2007 19:03:08 IST
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waiting for reply
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Woods are lovely dark and deep
But i have promises to keep
And miles to go before i sleep
And miles to go before i sleep
" HAVE A NICE DAY "
    
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Oct 2007 19:10:32 IST
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is the answer -3???
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3sin A + 5 cosA =5
3sinA= 5-5cosA
3sinA = 5(1-cosA)
3sinA( 1+ cosA) = 5( 1-cos2A) [ because cosA =/= -1 , otherwise from first equation , u'll get sinA>1 which is not possible]
3sinA(1+cosA) = 5sin2A
3(1+cosA) = 5sinA [If sinA =/= 0]
3= 5sinA - 3cosA
If sin A=0, then from first equation , cosA=1
So 5sinA - 3cosA = -3
You can also do this by squaring both the equations and then taking the square root.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Oct 2007 19:23:53 IST
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the answers are -3 and 3 both.
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Woods are lovely dark and deep
But i have promises to keep
And miles to go before i sleep
And miles to go before i sleep
" HAVE A NICE DAY "
    
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Oct 2007 19:25:59 IST
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yes 3 and -3 both.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Nov 2007 13:20:48 IST
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listen. if xcosA+ysinA=z,then,xsinA-ycosA= [ ] x2+y2-z2. hence the problem. please rate me also
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