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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Mar 2008 15:12:35 IST
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find all real solutions (x,y) to the equation
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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minimum value of RHS is 29
and max value of LHS is 29
so only one solution in (0,2pi) when both equal 29
RHS=29 at y=1/9
LHS=29(20/29 sin x - 21/29 cos x)
LHS=29sin-1(x-sin-1(21/29))
so x=npi+(-1)n(sin-1(21/29)),y=1/9 is the solution
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10 Mar 2008 15:25:43 IST
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Caution: Radioactive Hazard |
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10 Mar 2008 15:36:31 IST
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this is a qn based on boundary conditions(or something like that)--
max value of L.H.S= root(20^2 + 21^2)
=29
min value of R.H.S=
is at
y= -b /2a
=18 / 2*81
=1/9
at this value of y,
value of quadratic=1-2+30=29
thus we'll get soln only when L.H.S=R.H.S=29
for L.H.S to be 29
20 sin x - 21 cos x = 29
20/29 sin x - 21/29 cos x = 1
sin @=20/29
cos @=21/29
cos(@+x)=-1=cos(pi)
@+x=2npi (+ -) pi
x= [2npi (+ -) pi ]-@
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Impossible To be Impossible is Impossible |
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10 Mar 2008 15:37:46 IST
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Caution: Radioactive Hazard |
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10 Mar 2008 15:43:20 IST
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i think my speed has slowed down quite a bit!!
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Impossible To be Impossible is Impossible |
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10 Mar 2008 20:07:41 IST
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good answers...  thus:  hence  , and  therefore  let  then  , and therefore  hence  |
Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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