A ladder rest against a wall at an angle 'X' to the horizontal.Its foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down wall making an angle 'Y' with the horizontal then tan(X+Y) is equal to...???Plz explain the steps to solve dis prob.
Ans: (2ab) / (a^2-b^2)
Plz explain the steps to solve dis prob.
take initial height as p and distance of lader foot from wall be q and its length be L
now on taking the second condition height would be p-b and distance would be q+a
using 1 and 3 (just subtract)
using 2 and 4(just subtract)
divide the above two expression
apply tan2@ formulae u will get tan(x+y)...
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