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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Nov 2007 16:42:21 IST
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Simplify:- tan A/2(1+ secA)(1+ sec 2A)(1 + sec 4A)...(1 + sec 2nA)
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jst use secA = 1/ cosA
then apply 1 +cosA= 2 cos square A/2
then multiply n divide wid 2 power n
also divide n multiply wid sin square A / 2 n sin A
then u ll get the answer if u want a detailed solution nudge me then
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1 Nov 2007 17:50:50 IST
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tan A/2(1+ secA)(1+ sec 2A)(1 + sec 4A)...(1 + sec 2nA)
=(sinA/2 / cos A/2) ( cosA+1 / cos A) (1+ sec 2A)(1 + sec 4A)...(1 + sec 2nA)
=(sinA/2 / cos A/2) ( 2 cos2A/2 / cos A) (1+ sec 2A)(1 + sec 4A)...(1 + sec 2nA)
= (( 2sinA/2cosA/2 ) / cos A ) (1+ sec 2A)(1 + sec 4A)...(1 + sec 2nA)
= tan A (1+ sec 2A)(1 + sec 4A)...(1 + sec 2nA)
...
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...
...
=tan 2nA
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1 Nov 2007 21:32:28 IST
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Good work nadeemoidu.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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8 Nov 2007 20:16:54 IST
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im also ve got it.
if u want it i can explain u.
please rate me also
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