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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jul 2008 17:57:24 IST
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In tri. ABC base=6 &area=12 tha differ. of base angles is 60 degree,p.t. 8sinA-6cosA=3
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22 Jul 2008 20:11:01 IST
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If A is vertex then other two angles are 120-A/2 and 60-A/2.
The height is 4 and base is 6
So 4*(Cot(120-A/2)+Cot(60-A/2))=6
So tan(A/2-30)+tan(A/2+30)=1.5
Now write it in terms of sinA and cosA and get the desiered result
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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22 Jul 2008 20:14:54 IST
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can u plz tell me how the other angles are 120-A/2 and 60-A/2.
and also this step
4*(Cot(120-A/2)+Cot(60-A/2))=6
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SHREYA |
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