ans is correct plzz give d explanation
first we calculate 0.5*tan inverse 4/3.
let tanx = 4/3.
so tan(2*x/2) = [2tan(x/2)]/[1 - tan2(x/2)] = 4/3.
we get tan(x/2) = 1/2 , -2.
cosec(x/2) = root5.
so we have 32*cosec^2(0.5 * arctan4/3) = 160.
similarly let tany = 3/4.
we want tan(y/2). we can calculate to get, tan(y/2) = -3, 1/3.
(27/2)*sec^2(0.5*arctan3/4) = 15..
oops the reqd answer is187. sorry 4 d wrong answer of 160
i did it by calculator i got 175 as the ans i dont know what d hell is d actual ans .In d book it is given as 187
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