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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Multiple n submultiples!
Forum Index -> Trignometry like the article? email it to a friend.  
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m.viddya (101)

Scorching goIITian

Olaaa!! Perrrfect answer. 19  [22 rates]

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Q.tan(A+B)= n tan(A-B) then sin2A/sin2B =?
 
1.    1-n
----------
     1+n
 
 
2.  1+n
---------
    1-n
 
 
3.n-1
--------
  n+1
 
 
 
4.n+1
----------
  n-1
    
uday_zingtudor (931)

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tan(A+B)/tan(A-B) = n

expand this as (tanA+tanB)/1-tanAtanB
                         tanA-tanB/1+tanAtanB

Now expand tanA as sinA/cosA

U'll get sin(A+B)cos(A-B)/sin(A-B)cos(A+B) = n

use componendo dividendo and you'll get the answer as n+1/n-1

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don't get scared !!!
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rtiit (431)

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Olaaa!! Perrrfect answer. 75  bad job dude!! I dont approve of this answer! 1  [105 rates]

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the ans is n+1/n-1

xplaination givn by uday is perfect
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