Home » Ask & Discuss » Mathematics. » Trignometry « Back to Discussion

Trignometry

Scorching goIITian

Joined:	1 Nov 2007
Post:	218

5 Apr 2008 15:57:15 IST

0 People liked this

310

Multiple n submultiples!

None

Q.tan(A+B)= n tan(A-B) then sin2A/sin2B =?

1. 1-n

----------

1+n

2. 1+n

---------

1-n

3.n-1

--------

n+1

4.n+1

----------

n-1

Share this article on:

Comments (2)

Uday Prakash

Blazing goIITian

Joined: 7 Dec 2006

Posts: 504

5 Apr 2008 20:52:17 IST

Like 1 people liked this

tan(A+B)/tan(A-B) = n

expand this as (tanA+tanB)/1-tanAtanB
tanA-tanB/1+tanAtanB

Now expand tanA as sinA/cosA

U'll get sin(A+B)cos(A-B)/sin(A-B)cos(A+B) = n

use componendo dividendo and you'll get the answer as n+1/n-1

~Cheerio!!!

Tanmay

Blazing goIITian

Joined: 6 Sep 2007

Posts: 956

5 Apr 2008 21:09:36 IST

Like 0 people liked this

the ans is n+1/n-1

xplaination givn by uday is perfect

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team