The Sin (x2) is definitely a non periodic function, it is oscillatory between +1 and -1 with continuously reducing period as'x' progresses.
Proof of its non periodicity.
Let us assume that Sin (x2) is a periodic function with period T
Thus Sin ((x + T)2) = Sin (x2)
or Sin (x2 + 2T + T2) = Sin (x2)
Which means that the periodicity of the function is 2T + T2, but we have assumed that it is T
so 2T + T2 = T
or T + T2 = 0
or T = 0 or -1, which is not possible.
Thus our assumption that the function Sin (x2) is periodic is false
The Sin (x2) is definitely a non periodic function, it is oscillatory between +1 and -1 with continuously reducing period as'x' progresses.
Proof of its non periodicity.
Let us assume that Sin (x2) is a periodic function with period T
Thus Sin ((x + T)2) = Sin (x2)
or Sin (x2 + 2T + T2) = Sin (x2)
Which means that the periodicity of the function is 2T + T2, but we have assumed that it is T
so 2T + T2 = T
or T + T2 = 0
or T = 0 or -1, which is not possible.
Thus our assumption that the function Sin (x2) is periodic is false