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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: please answer
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[Post New]16 Apr 2008 13:54:08 IST
    Subject: please answer
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iit009 (24)

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if cot? equals to the integral solution of the inequality 4x^2 -16x +15<0 and sin? equals to the slope of the bisector  of the first quadrant, then sin(?+?)sin(?-?) is equal to:
    
[Post New]16 Apr 2008 16:35:03 IST
    Subject: Re:please answer
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als (12)

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I am not being able to understand the difference between the angles with sin and with cot. If they are equal, then the answer is definitely zero because sin 0=0.
Please clarify my doubt.
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[Post New]16 Apr 2008 20:18:42 IST
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sboosy (3011)

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4x^2-16x+15<0 \\ \\ \Rightarrow (2x-3)(2x-5)<0 \\ \\ \mbox{Only integral solution is} \ x=2 \ \Rightarrow \cot(\theta_1)=2 \ \Rightarrow \sin(\theta_1)=\frac{1}{\sqrt{5}} \\ \\ \mbox{Bisector of 1st quad means slope} \ =\tan(45) =1 = \sin(\theta_2) \\ \\ \sin(\theta_1+\theta_2)*\sin(\theta_1-\theta_2) = \sin^2(\theta_1) - \sin^2(\theta_2) = \frac{1}{5}-1 = \frac{-4}{5}
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[Post New]17 Apr 2008 13:07:43 IST
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Decoder (331)

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they r diffrent angles i think..otherwise ques. doen't have any meaning..
Diamonds r formed under greatest pressures..
so r the champs.

Kriteesh..


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[Post New]17 Apr 2008 15:02:22 IST
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iit009 (24)

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how u get the integral solution as 2
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