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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Mar 2007 15:11:49 IST
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In triangleABC if a,b,A are given & c1 ,c2 are 2 values of 3rd side,
(1)then sum of areas of two triangles with sides a,b,c1 & a,b,c2
(2) {(c1-c2)²+(c1+c2)²}tan²A is
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7 Mar 2007 23:30:32 IST
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cosA=b^2+C^2-A^2/2bc implies2bc cosA=b^2+c^2-a^2 implies c^2-( 2bcosA)c+(b^2-a^2)=0 imp c1+c2=2bcosA & c1c2=b^2- a^2 area1=1/2bc1sinA .........(1) area2=1/2bc2sinA........(2) (1)+(2)=1/2bsinA(c1+c2)=1/2bsinA*2bcosA=b^2/2sin2A
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