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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Jul 2008 19:15:07 IST
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sin(n+1)Asin(n-1)A+cos(n+1)Acos(n-1)A=cos2A
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18 Jul 2008 08:25:48 IST
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(n+1)A=a
(n-1)A=b
Hence our given eqn is of from cos(a).cos(b)+sin(a).sin(b) which is cos(a-b)
cos((n+1)-(n-1))A=cos(2A)
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