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Trignometry

Blazing goIITian

Joined:	4 Feb 2008
Post:	590

18 Dec 2008 21:27:30 IST

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598

prove that...........

None

/1- =1+

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Comments (6)

Aditya

Blazing goIITian

Joined: 4 Feb 2008

Posts: 590

18 Dec 2008 21:41:28 IST

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its a xth class question come on yaar someone try!

chinmay

Cool goIITian

Joined: 18 Dec 2008

Posts: 56

18 Dec 2008 21:45:06 IST

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cross multiply,since (1-cosx)is not 0.

i.e. to prove becomes:

sinx *tanx=(1-cosx)*(1+secx)

i.e.

sinx*tanx=secx-cosx

i.e.

sinx*tanx=1-(cosx)^2/cosx

i.e.

sinx*tanx=(sinx)^2/cosx

i.e.

sinx*tanx=sinx*tanx

which is true.

pls rate.

suraj

Cool goIITian

Joined: 4 Dec 2008

Posts: 30

18 Dec 2008 23:10:50 IST

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another method:

Hence proved.

Rajat Khanduja

Scorching goIITian

Joined: 14 Dec 2007

Posts: 266

19 Dec 2008 09:05:42 IST

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Another method as this is a class X question

Replace tanx = sinx / cosx

then, write sinx = ( 1 - cosx ) (1+ cos x )
And its done.

Sagar Saxena

Forum Expert

Joined: 8 Oct 2008

Posts: 7221

19 Dec 2008 20:09:48 IST

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sinx *tanx / ((1-cosx) =(1+secc x

sin² x / cos x ((1-cosx)

1+cosx / (cos x)

(1+secc x )

hyd

New kid on the Block

Joined: 20 Dec 2008

Posts: 13

20 Dec 2008 21:33:30 IST

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sinx.tanx/[1-cosx]=[1+secx]

sinx.tanx=[1+secx].[1-cosx]

sinx.tanx=1+secx-cosx-1

sinx.tanx=sinx.tanx

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