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Trignometry

Cool goIITian

Joined:	12 Jul 2009
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26 Jul 2009 16:54:58 IST

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Prove that (SEC thita -TAN thita +1)/(SEC thita +TAN thita +1) =(1-SIN thita)/(COS thita) .

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Prove that (SEC thita -TAN thita +1)/(SEC thita +TAN thita +1) =(1-SIN thita)/(COS thita) .

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vnkt. swaroop

Blazing goIITian

Joined: 13 Jun 2008

Posts: 611

26 Jul 2009 20:04:01 IST

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(secx -tanx+1)/(secx+tanx+1)

={(secx+1)-tanx}/{(secx+1)+tanx}

multiply numerator and denominator with {(secx+1)-tanx} then you will get:-

=(sec^2x+1+tan^2x+2secx-2tanx-2secxtanx)/(sec^2x+1+2secx-tan^2x)

=(2sec^2x+2secx-2tanx-2secxtanx)/(2+2secx)

={secx(secx+1)-tanx(secx+1)}/{1+secx}

={(1+secx)(secx-tanx)}/{1+secx}

=secx-tanx

=(1-sinx)/(cosx)

tell me whether i am correct or not?

reply is must.

Sarthak

Blazing goIITian

Joined: 21 Aug 2007

Posts: 385

26 Jul 2009 20:13:12 IST

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You didn't have to type "thita" over and over again.

You could've just gone with x.

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