To Prove: cos A (tan A + 2) (2 tan A +1) = 2 secA + 5 sinA
( tanA + 2 ) ( 2tanA + 1 )
= 2tan^2(A) + 5tanA + 2 ( silly-mistake prone area )
= 2( 1 + tan^2(A) ) + 5 tanA
= 2 sec^2(A) + 5 tanA
= 2 secA / cosA + 5sinA/ cosA
cosA ( tanA + 2 ) ( 2tanA + 1 ) = 2secA + 5sinA
Proved.
The end.
To Prove: cos A (tan A + 2) (2 tan A +1) = 2 secA + 5 sinA
( tanA + 2 ) ( 2tanA + 1 )
= 2tan^2(A) + 5tanA + 2 ( silly-mistake prone area )
= 2( 1 + tan^2(A) ) + 5 tanA
= 2 sec^2(A) + 5 tanA
= 2 secA / cosA + 5sinA/ cosA
cosA ( tanA + 2 ) ( 2tanA + 1 ) = 2secA + 5sinA
Proved.
The end.