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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 09:43:49 IST
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Q.The ratio of areas of regular hexagons which are inscribed in a triangle of radius r and circumscribed to the same circle is? 1. 1:2 2. 2:3 3. 3:4 4. 1:3
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 11:30:19 IST
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what do you mean by triangle of radius r?
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"I a universe of atoms.......an atom in the universe" |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 11:35:13 IST
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so many questions at a single stretch? Looks like you have posted your entire homework here..... 
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"I a universe of atoms.......an atom in the universe" |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 11:41:17 IST
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or it could be that the particular person in question is presently revising this chapter  
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 12:01:09 IST
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well...well..well...no solution still/?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 12:04:26 IST
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wat is a triangle of radius r precisely??
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 12:14:55 IST
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area oh hexagon inscribed in incircle =6*1/2*r^2cos30
area of hexagon ins in circumcircle=6*1/2*R^2cos30
so to find ratio v need r/R where r is inradius R is circumrad r=4RsinA/2sinB/2sinC/2 so ratio is 4sinA/2sinB/2sinC/2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 12:16:18 IST
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if u r askin min value then it is 1/2
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Nitwit Blubber Odment Tweak
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Question is wrong she means that the hexagon is within the circle in the first case and then in the next case , the circle is circumscribed by the hexagon
So in the first case lets take that the hexagon is within the circle. so 6 equilateral triangles are formed,
hence area = 6 * 3/4 r^2
for the second one area = 6 * 3/4 a^2 where a = 2r/ 3
So ratio of areas = 3 : 4
So triangle part has to be excluded.
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From J.R.R. Tolkien's 'The Lord of the Rings':
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