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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Sep 2007 11:21:38 IST
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the range of f(x) = 1/ 5-3 cos2x any 1 tell me how to find the range os it and some more examples if u have....plzzz
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cos2x varies from -1 to 1
so here the range is from 1/(5+3) to 1/(5-3)
i.e. from 1/8 to 1/2
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21 Sep 2007 13:49:22 IST
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-3 <= 3cos2x <= 3
Now add 5 to each of them :
5 - 3 <= 5 - 3cos2x <= 5 + 3
2 <= 5 - 3cos2x <= 8
1/2 >= 1/(5 - 3cos2x) >= 1/8
Hence the range is [1/8,1/2]
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 4 points
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