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Trignometry

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31 Jan 2012 15:08:47 IST

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reduce equation of line 3x-4y+4=0 and 2x+4y-5=0 to the normal form and hence find which l

Mathematics

reduce equation of line 3x-4y+4=0 and 2x+4y-5=0 to the normal form and hence find which l

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sidharthsekharsahoo

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Joined: 9 Jan 2012

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31 Jan 2012 18:20:46 IST

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the normal form of 3x-4y+4=0 is 3x/5-4y/5=4/5 and 2x+4y-5=0 is 2x/(20)^1/2 + 4y/(20)^1/2 =5/(20)^1/2 but what is ur ques.

please write the full ques

Bipin Dubey

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Joined: 23 Jan 2007

Posts: 7942

31 Jan 2012 19:14:47 IST

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Normal forms are

$\frac{3x-4y+4}{\sqrt{3^2+(-4)^2}}=0 \Rightarrow\; \; \frac{3}{5}x-\frac{4}{5}y+\frac{4}{5}=0$

$\frac{2x+4y-5}{\sqrt{2^2+4^2}}=0 \Rightarrow\; \; \frac{1}{\sqrt{5}}x+\frac{2}{\sqrt{5}}y-\frac{\sqrt{5}}{\sqrt{4}}=0$

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