|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jul 2008 20:47:25 IST
|
|
|
sin11AsinA + sin7Asin3A / cos11AsinA + cos7Asin3A
|
|
|
|
|
|
|
|
2sin11AsinA +2 sin7Asin3A /2 cos11AsinA + 2cos7Asin3A
cos12A-cos10A+cos10A-cos4A/sin12A-sin10A+sin10A-sin4A cos12A-cos4A/sin12A-sin4A sin8Asin4A/cos8Asin4A=tan8A
|
SHREYA |
this reply: 7 points
(with 1 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|