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Community Discussion Question:
trignometry
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Trignometry
Author
Message
20 Nov 2006 20:42:25 IST
Subject:
trignometry
srahul
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sec
+tan
=100,find the value of tan
+cot
(please solve it for me)
21 Nov 2006 19:32:19 IST
Subject:
Re:trignometry
edison
(
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Blazing goIITian
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Q) sec
+tan
=100,find the value of tan
+cot
Since, sec
+tan
=100
or 1/cos
+ sin
/cos
= 100
or 1+ sin
= 100cos
Squaring both the sides
(1+ sin
)(1+ sin
)= 10000 (cos
)((cos
or (1+ sin
)(1+ sin
)= 10000(1 - s
in
2
)
or (1+ sin
)(1+ sin
)= 10000(1 - s
in
)(1 + s
in
)
or (1+ sin
) = 10000(1 - s
in
)
or sin
= 9999/10001 (1)
therefore cos
=[(1 -
(9999/10001)
2
]
1/2
= (200/10001)
(2)
now ,
tan
+cot
=sin
/cos
+ cos
/sin
= 1/sin
cos
sustituting the values of sin
and cos
from (1) and (2) we obtain,
tan
+cot
= (10001)
2
/[9999
×200]
The most incomprehensible thing about the world is that it is
at all comprehensible.
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22 Nov 2006 20:39:07 IST
Subject:
Re:trignometry
srahul
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THANK YOU SIR
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24 Nov 2006 20:17:37 IST
Subject:
Re:trignometry
pranni
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sec
+tan
=100
sec
-tan
=1/100 since sec
2
-tan
2=
=1 secc
-tan
=1/sec
-tan
=1/100 there4 subtractinng 2 eqns tan
=9999/200
cot
=200/9999 cot
+tan
=10001x10001/9999x200
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