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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: trignometry
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srahul (0)

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sec+tan=100,find the value of tan+cot
 
(please solve it for me)
    
edison (4435)

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Q) sec+tan=100,find the value of tan+cot
Since, sec+tan=100
or 1/cos + sin/cos = 100
or 1+ sin = 100cos
Squaring both the sides
(1+ sin )(1+ sin )= 10000 (cos)((cos
or (1+ sin )(1+ sin )= 10000(1 - sin2)
or (1+ sin )(1+ sin )= 10000(1 - sin)(1 + sin)
or  (1+ sin ) = 10000(1 - sin)
or  sin = 9999/10001       (1)
therefore cos =[(1 - (9999/10001)2]1/2= (200/10001)              (2)
now ,
 tan+cot =sin/cos + cos/sin
                  = 1/sincos
 sustituting the values of sin  and cos from (1) and (2) we obtain,
tan+cot = (10001)2/[9999×200]
 

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THANK YOU SIR
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sec
+tan=100 sec-tan=1/100 since sec2-tan2==1 secc-tan=1/sec-tan=1/100 there4 subtractinng 2 eqns tan=9999/200 cot=200/9999 cot+tan=10001x10001/9999x200
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