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Trignometry

sneha kulkarni's Avatar
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15 Mar 2007 11:29:40 IST
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trignometry......
None

in triangle ABC p.t
sin2A+sin2B+sin2C=4.sinA.sinB.sinC


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vishak p's Avatar

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15 Mar 2007 11:33:44 IST
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in this quest. sneha first use the formula for sin X + sin Y = 2 sin (X+Y)/2 sin (X-Y)/2 , then substitute the relation A+B+C = pie
it will be a little long, but it will come !
do ask if it doesn't come
sneha kulkarni's Avatar

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15 Mar 2007 11:43:45 IST
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yes i m trying but tell me....why v should substitute A+B+C=pi......pls tell me
vishak p's Avatar

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15 Mar 2007 11:45:10 IST
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this is because in a triangle the sum of the angles is = pie !
sneha kulkarni's Avatar

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15 Mar 2007 11:47:13 IST
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wait.............if we substitue A+B+C=180........
sneha kulkarni's Avatar

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15 Mar 2007 11:47:57 IST
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yeah...i got it! thanks..........
vishak p's Avatar

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15 Mar 2007 11:48:49 IST
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always welcome !

Cool goIITian

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15 Mar 2007 11:51:07 IST
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combine sin 2B and sin 2B and substitute sin C as (pi - A+B) solving further u'll get it right
ruhi agrawal's Avatar

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15 Mar 2007 11:54:24 IST
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one more thing.........this relation is quite useful in solving prob. so learn it......u shud know this relation...ok
cheers
sneha kulkarni's Avatar

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15 Mar 2007 12:03:23 IST
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thanks supriya and ruhi............

Blazing goIITian

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15 Mar 2007 15:09:51 IST
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some more imp results.....in a triangle....
1) sin2A+sin2B+sin2C=4 sinAsinBsinC
 
2)cos2A+cos2B+cos2C= -1-4cosAcosBcosC
 
3)cosA+cosB+cosC= 1+4 sin(a/2)
 
4)sin^2 A=2+2cosA
 
5)cos^2 A=1-2cosA
 
6)sin2A+sin2B-sin2C = 4cosAcosBsinC
 
7)cos2A-cos2B+cos2C= 1-4sinAcosBsinC
 
8)sinA+sinB-sinC=4sin(A/2)sin(B/2)cos(C/2)
 
9)cosA+cosB-cosC= -1+4cos(A/2)cos(B/2)sin(C/2)
 
hope u find these useful.......
                                                 Goutham.K
 
sneha kulkarni's Avatar

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15 Mar 2007 17:17:11 IST
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hey thanks a lot.............gautham



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