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Trignometry
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19 Oct 2011 12:02:03 IST
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(1+tan46*tan14)(1 + tan32*tan74)
or, (cos46*cos14 + sin46*sin14)(cos32*cos74 + sin32*sin74)/(cos46*cos14*cos32*cos74)
or, [cos(46-14)*cos(32-74)]/(cos46*cos14*cos32*cos74)
or, [cos32*cos42]/(cos46*cos14*cos32*cos74) = cos42/(cos46*cos14*cos74)
i used this -
1 + tanA*tanB = cos(A-B)/(cosA*cosB).














cot16*cot44+cot44*cot76-cot76*cot16 = 3
or, tan46*tan74 + tan46*tan14 - tan14*tan74 = 3
or, tan46*tan74 + tan46*tan14 - tan14*tan74 + 1 = 4
or, LHS = tan74(tan46-tan14) + (1+tan46*tan14)
or, tan74(tan32)(1+tan46*tan14) + (1+tan46*tan14)
or, (1+tan46*tan14)(1 + tan32*tan74)
or, cos32*cos42/(cos46*cos14*cos32*cos74)
or, cos42/(cos46*cos14*cos74) .....(1)
now cos(x)*cos(60-x)cos(60+x) = 1/4cos(3x)
put x = 14 to get
cos46*cos14*cos74 = 1/4*cos42 putting this in (1)
we get LHS = 4 = RHS.
hence proved....
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