IIT JEE , AIEEE Forum - Mathematics , Trignometry

KHUSHBOO_KASHYAP

turn into answer pls

Q sina+sinb+sinc=3 then cosa+ cosb+cosc=?

(a) 1 (b) 2 (c) 1 (d) 0

DON007

hey look............the answer of

sina+sinb+sinc=3............can be in only one manner..............that is............

a=b=c=pi/2...............okkkkkkkk

then only

sinpi/2+sinpi/2+sinpi/2=3

therefore.............

cos pi/2 +cos pi/2 +cospi/2 =0..............

thanku

visioniit

sin a +sin b+sin c=3 if and only if a=b=c=90
thus, cos a +cos b+cos c= cos 90+ cos 90+ cos 90
=0

for_succes

this question was already asked
neway the answer is '0'

sanchay_1991

obviously the ans is zero

the above solns are correct

sanchay_1991

but if u consider for a triangle

the max walue

of sina +sin b + sin c will not be three