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Trignometry
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Rajat Barve
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Joined: 31 Jan 2007
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22 Feb 2007 23:58:17 IST
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even i had the same doubt.but as far as i know the proof of this inequality makes use higher engineering mathematics which includes a complicated taylor's theorem series and partial differentiation
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23 Feb 2007 20:23:26 IST
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i m not satisfied with that answer ! i mean someone asks me to just derive the minimum value for cos A + cos B + cos C in a triangle, then how shall i proceed ?? also, why will sin A/2 + sin B/2 + sin C/2 be maximun when all the angles are equal to each other ??
24 Feb 2007 14:41:08 IST
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we know that in a
cosA+cosB+cosC=1+r/R
so,cosA+cosB+cosC>1
so,there cannot exist minimum value
sincewe know that cosA+cosB+cosC=1+r/R sinX >0 in triangle,
A.M >= G.M is applicable & and so maximum is when A.M = G.M & possible for only equilateral triangle ,so, at A=B=C,sinA+sinB+sinC is maximum
cosA+cosB+cosC=1+r/Rso,cosA+cosB+cosC>1
so,there cannot exist minimum value
sincewe know that cosA+cosB+cosC=1+r/R sinX >0 in triangle,
A.M >= G.M is applicable & and so maximum is when A.M = G.M & possible for only equilateral triangle ,so, at A=B=C,sinA+sinB+sinC is maximum

25 Feb 2007 18:16:39 IST
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sin A/2 + sin B/2 + sin C/2 will be minimum.
Applying AM>=GM and it will be minimum when all the entities are equal.
Vish.....when there are 3 negative numbers then its GM will be root of some negative number which is undefined.Hence the inequality is applicable only for positive numbers.
Hope its clear now.
Best Wishes
Applying AM>=GM and it will be minimum when all the entities are equal.
Vish.....when there are 3 negative numbers then its GM will be root of some negative number which is undefined.Hence the inequality is applicable only for positive numbers.
Hope its clear now.
Best Wishes












