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Ask iit jee aieee pet cbse icse state board experts Expert Question: trigonometry
Forum Index -> Trignometry like the article? email it to a friend.  
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[Post New]5 Jan 2007 22:31:04 IST
    Subject: trigonometry
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sucess_seeker (5)

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sin5A= 5cos4AsinA-10cos2sin3A+sin5A
sikha
Success is how high you bounce when you hit bottom.
    
[Post New]6 Jan 2007 22:08:43 IST
    Subject: Re:trigonometry
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edison (4384)

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sin5A = sin (A+4A)
 
= sinA cos4A + cosA sin4A
 
= sinA (cos2 2A - sin2 2A) + 2sin2A cos2A cosA
 
= sinA[(cos2A - sin2A)2 -4sin2A cos2A] + 4sinA cos2A(cos2A - sin2A)
 
=sinA[cos4A+sin4A - 2sin2A cos2A-4sin2A cos2A]+ 4sinAcos4A - 4sin3Acos2A
 
= sinA[cos4A+sin4A - 6sin2A cos2A]+ 4sinAcos4A - 4sin3A cos2A
 
= sinA cos4A+sin5A - 6sin3A cos2A+ 4sinAcos4A - 4sin3A cos2A
 
= 5cos4AsinA - 10cos2sin3A + sin5A
 
The most incomprehensible thing about the world is that it is

at all comprehensible.
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[Post New]7 Jan 2007 18:29:04 IST
    Subject: Re:trigonometry
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sulekha_hi (34)

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thank you
Be like a postage stamp.Stick to anything until you get there.
Sulekha
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