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Ask iit jee aieee pet cbse icse state board experts Expert Question: trigonometry
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[Post New]22 Jul 2007 18:09:06 IST
    Subject: trigonometry
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rohan12 (0)

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[1+tan]2+[1+cot]2=[sec+cosec]2         how?
 
    
    
[Post New]22 Jul 2007 18:57:56 IST
    Subject: Re:trigonometry
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elessar_iitkgp (2264)

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[1+tan]2+[1+cot]2 = (sin + cos)2/cos2 + (sin + cos)2/sin2
= (sin + cos)2(sec2 + cosec2) = (1+2sincos)(sec2 + cosec2)
=sec2 + cosec2 + 2sincossec2 + 2sincoscosec2
=sec2 + cosec2 + 2sin/cos + 2cos/sin
= sec2 + cosec2 + 2(sin2 + cos2)/sincos
= sec2 + cosec2 + 2cosecsec
= (sec + cosec)2


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