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Trignometry

vishak p's Avatar
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20 Feb 2007 14:34:02 IST
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trigonometry
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the number of all possible triplets (a1,a2,a3) such that
 
a1 + a2 (cos 2x ) + a3 sin2 x = 0 for all x is ;;
 
a. zero                            b. one
c. three                           d.infinte


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vishak p's Avatar

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20 Feb 2007 14:48:42 IST
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???
vinu's Avatar

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20 Feb 2007 14:52:31 IST
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Hi vish0001,
given is........a1+a2(1-2sin2x)+a3sin2x=0;
a1+a2=sin2x(2a2-a3) ;
If the above eq shud be satisfied  x , u shud 've (2a2-a3) = 0;
i.e; 2a2=a3 ; a1= - a2 ;
a1:a2:a3= -1:1:2 ;
So, u can've infinite values for (a1,a2,a3).
 
vishak p's Avatar

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20 Feb 2007 14:56:28 IST
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i am not able to understand why 2a2-a3 should be equal to 0 ??
vishak p's Avatar

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20 Feb 2007 14:57:47 IST
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also , vinu can u please answer the other questions asked by me in the expert level by me ?? please i am dying for answers !
Ramya Hegde's Avatar

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20 Feb 2007 16:02:50 IST
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for the given condition to be true for all x, the coefficients must be zero, so in that case, whatever may be the value of x, u always get the LHS as zero, i.e. to get LHS as identity, u need a1=-a2 and 2a2=a3.
Bipin Dubey's Avatar

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21 Feb 2007 14:45:16 IST
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a1 + a2cos2x + a3sin2x = 0
 
=> a1 + a2(1-2sin2x) + a3sin2x = 0
=> (a1 + a2) + (a3 - 2a2)sin2x = 0
 
Since its independent of x then coefficient of sin2x is 0.
i.e. (a3 - 2a2) = 0
and (a1 + a2) = 0
 
=> a1:a2:a3 = (-1):1:2
 
Hence infinite triplets are possible.
vishak p's Avatar

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21 Feb 2007 16:30:14 IST
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sir, why has the coefficient of sin square x being written down as 0 ? i mean we can do thi type of arrangement only in vectors, complex numbers but not in algebra ! please explain!
CyBorG's Avatar

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21 Feb 2007 18:41:16 IST
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See Vish when the co-efficient of sin(square)x is zero whatever may be the value of x the equation will be true.



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