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Trignometry
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vishak p
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Joined: 9 Feb 2007
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20 Feb 2007 14:48:42 IST
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21 Feb 2007 14:45:16 IST
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a1 + a2cos2x + a3sin2x = 0
=> a1 + a2(1-2sin2x) + a3sin2x = 0
=> (a1 + a2) + (a3 - 2a2)sin2x = 0
Since its independent of x then coefficient of sin2x is 0.
i.e. (a3 - 2a2) = 0
and (a1 + a2) = 0
=> a1:a2:a3 = (-1):1:2
Hence infinite triplets are possible.


a1+a2=sin2x(2a2-a3) ;
x , u shud 've (2a2-a3) = 0;








