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Ask iit jee aieee pet cbse icse state board experts Expert Question: Trigonometry problem
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Chinzon (0)

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Prove that tanx+tany+tanz = tanx.tany.tanz, where x,y,z are any three angles.
    
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Isn't there anybody who can answer this? This is not fair. I need a solution.


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aankurverma (1310)

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x + y + z = pi
tan(x + y + z) = tanx + tany + tanz - tanx.tany.tanz/1 - tanx.tany - tany.tanz - tanz.tanx

tanx + tany + tanz - tanx.tany.tanz = 0
   tanx + tany + tanz = tanx.tany.tanz
 
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Chinzon (0)

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How can x+y+z = pi when it is ? Please answer this.

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aankurverma (1310)

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iff x,y,z are d angles of a triangle then itz true hence tanx + tany + tanz will not equal to tanx.tany.tanz
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puneet (3573)

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hey
 
ur questoin is not correct .. only when x, y, z are the angles of the triangle do this property hold else not
 
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Puneet Agrawal
IIT Delhi
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kmmankad (46)

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The question shall be true if the angles are something like 50,70,20
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sandeep.master (12)

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the question is incorrect . it should be tanx.tany.tanz=tanz-tanx-tany
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prathima (49)

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sandeep.............
can u prove it plz



GBXDHNXDFNHBHRSDRGWEASGSEDH
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akumar_ak (11)

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its true that if the angles are of a triangle,then only ankur will be right
question,but,is incorrect

life's like a game
play it,enjoy it,accept defeats too,and finally win it
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kmmankad (46)

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70=50+20
take tan on both sides
tan70=tan50+tan20/1-tan50tan20
tan70-tan70tan50tan20=tan50+tan20
tan70-tan20-tan50=tan70tan50tan20
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shyam_nair_s (129)

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yaaa.....the ques is incorrect. its a very popular question. came in our school exams also . u might have made a printing mistake in ur ques.
X+ Y+ Z =   shud have been given.

An optimist stays until midnight to see the new year ..a pessimist stays up to make the old year leaves...
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aratrika (82)

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IF x,y,z are the angles,then
x+y+z=0
tan (x+y+z)= tan 0 degree =0
 
or, (S1-S3)/1-S2 =0       [ by properties of triangle]
so, S1= S3
or tan x+ tany+tan z=tanx. tany. tanz
 
so the question is not wrong!
 
 
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ishali_tiwari (0)

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u know the formula???


ok..............a+b+c=pi


that means a+b=pi-c


take tan both sides.


tan (a+b)=tan(pi-c)


tan a + tan b /1 - tan a *tan b=-tan c


tan a + tan b= - tan c + tan a * tan b * tan c


tan a + tan b + tan c=tan a *tan b*tan c


hence proved

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