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Vectors

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Post:	234

20 Mar 2008 07:55:26 IST

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Find the image of the point (1, 6,3) in the line x/1=y-1/2=z-2/3 plz reply soon

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Partha Pratim

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Joined: 15 Mar 2007

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20 Mar 2008 08:04:45 IST

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(1,0,7)

ANUPAM DEV

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20 Mar 2008 08:06:41 IST

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plz give the solution

Partha Pratim

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Posts: 336

20 Mar 2008 08:10:13 IST

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let the line x/1=y-1/2=z-2/3=k
any point on this line is (k,2k+1,3k+2)
direction ratios of the line joining this point and (1,6,3) is
(k-1,2k-5,3k-1)
this line and the given line are perpendicular
therefore l1l2+m1m2+n1n2=0
1.(k-1)+2(2k-5)+3(3k-3)=0
solving we get k=1
the point on the line is 1,3,5
thi point is the midpoint of the reqd point and given point,
so put the section formula and the answer will be(1,0,7)

Partha Pratim

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Joined: 15 Mar 2007

Posts: 336

20 Mar 2008 08:14:21 IST

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samajh mein aaye toh rate karna

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