Cartesian equation is the one which you posted.
To find direction rations,make x,y and z independent of any terms
So, line is
6(x- 1/3)= 3(y+1/3)= 2(z-1)
(x- 1/3)/(1/6)= (y + 1/3)/(1/3)= (z-1)/(1/2)
So direction ratios are 1/6,1/3 and 1/2
Since this line passes through (1/3,-1/3,1) and has above direction ratios
Its vector eqn is given by
[(1/3)i + (-1/3)j +k] + m[(1/6)i + (1/3)j + (1/2)k]=0
where m is any constant.
Thanks a lot:)
Could you tell me what exactly vector equation is?
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