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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:05:45 IST
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If a,b and c are unit vectors ,then Ia-bI^2 + Ib-cI^2 + Ic-aI^2 does not exceed
4
9
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6
5 salutes to one who ans and explain his ans correctly.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:07:40 IST
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bhai plz make the questiona bit more clear plz??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:13:01 IST
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wat is l yaar????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:20:10 IST
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ans. max. value is 9 !
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:23:23 IST
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without havin ne info abt l how can u solve neways the logic behind this prob is assume v= ai+bj+ck w= li+lj+lk we no that a.b<= mod a mod b similarly sme x= l^2i +l^2j+l^2k again a.b<= mod a mod b then add them to get the req sol
HOPEFULLY IT HELPS ne doubts nudge me
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:23:31 IST
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2(a^2+b^2+c^2)-2(a.b+b.c+c.a)
now , let a,b,c be such that they have 120 degree angle b/w eachother. hence, 2(1+1+1)-2(-1/2-1/2-1/2) =6+3 =9!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:35:31 IST
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hopefully i could make it clear
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Dec 2007 20:41:03 IST
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Re:5 salutes assured...gud one
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