|
| physics chemistry maths science forums |
|
|
|
| |
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 May 2008 13:47:22 IST
|
|
|
a X[b X(c X a) + (p X q)]=? ans:(a.q)p+(b-a)(a X c) how?
|
|
|
|
|
|
|
|
I got a diff ans but I think it is correct.
bX(cXa)=(b.a)c-(b.c)a aX[bX(cXa)]=(b.a)(aXc) [since aXa=0,second term is 0]
Now,aX(pXq)=(a.q)p-(a.p)q.So,the ans is (b.a)(aXc)+(a.q)p-(a.p)q
|
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
14 May 2008 14:08:44 IST
|
|
|
i think @allamraju is correct
even i got the same ans
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
14 May 2008 14:12:22 IST
|
|
|
i wrote a wrong answer b4...ur answer is perfect.....thnks..
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
