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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Sep 2007 18:01:50 IST
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A vector dosent have a component in the direction perpendicular to it. But if we resolve a vector along X and Y axes and resolve the component on Y axis in the direction perpendicular to the vector we get the perpendicular component of the vector. How??
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Sep 2007 18:22:24 IST
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when a vector is resolved along x axis and y axis we take into account the angle theta between the vector and x axis usually. the angle between the y axis is (90-theta). when the y axis component is resolved with respect to vector the vector becomes x axis and (90-theta) now becomes the angle . the other resolved component would thus be perpendicular to the original vector..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Sep 2007 18:29:15 IST
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But a vector cannot have a component perpendicular to it right???
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Sep 2007 18:57:03 IST
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yes.. but when the perpendicular vector is obtained you are resolving the y axis, which is not the original vector
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Sep 2007 18:58:01 IST
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You are resolving the component on the Y axis only . If you resolve the component on the X axis also , it will be equal and opposite and hence they will be cancelled .
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i think components are magnitudes of the original vector in specified directions and it is wrong to talk abt component of a component
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