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Ask iit jee aieee pet cbse icse state board experts Expert Question: Doubt on vectors.
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jv604 (0)

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1). if  vector a, vector b ,vector c are the position vectors of the non- collinear points A,B,C resp. then show that a*b+b*c+c*a is perpendicular to the plane of ABC.(* is actually cross).,where a,b,c are vectors.
 
2). Let a ,b,c be 3 non zero vectors. if a.(b*c)=0 and b,c are not parallel then prove that a=b+kc  where  and k are some scalars.
 
3). if a,b,c represent the vectors BC,CA and AB of a triangle ABC then show that a*b=b*c=c*a.
(* is actually cross product in vectors in all 3 sums)
 
    
ayshwarya (241)

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ans 4 3rd 1 a=OC-OB , b=OA-OC , c=OB-OA hence by cross product v wud get OA*OB+OB*OC+OC*OA
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nishantsingh89 (970)

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1)
as a,b,c lie  in same plane so
a*b is perp. to the plane ABC
b*c is perp. to the plane ABC,
similarly for c*a...

as a*b, b*c, c*a all lie in plane perpendicular to tht of ABC,
so a*b +b*c+c*a lies in plane perpendicular to tht of ABC

aliter

let a*b+b*c+c*a lie in any plane perp to ABC
then its dot product with any of a,b,c shud be zero
on taking dot product with a
we get [aba] + [bca] + [caa]
[aba]=[caa]=0
and since b,c,a are coplanar so [abc] =0
thus dot product is zero so the vector lies in plane perp to ABC
 




The heights which great men reached and kept, Were not attained by sudden flight, They, whilst their companions slept, Were toiling upwards in the night....
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studyid (1654)

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hey jv604,
  see i have a sol. to yr 3rd q.
  it is as follows :

 see vector a =BC vctor, then vector b = AC vector and lastly vctor c=AB vctor.

now since these three vectors a,b n c for a , it is very obvious acc, to law of vector addition, that a+b+c=0.

Now thats a imp. relation.

 now take cross product of a on both the sides,

a x (a+ b + c) = a x 0
a x b + a x c =0
axb=cxa.----(1)

now take cross product on both sides with b

b x (a+b+c)=b x 0
bxa+bxc=0
bxc=axb---(2)

hnce by 1 & 2,
axb=bxc=cxa


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ayshwarya (241)

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4 2nd quesn lets cum from end its a=lambda b +kc hence

[ ( lb+kc)*b] . c

= k(c*b) . c =0 hence proved
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nishantsingh89 (970)

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2) a.(b*c)=[abc] =0

thus abc are  coplanar vectors

and if three vectors lie in a plane then any vector can be expressed as a linear combination of other 2 vectors


The heights which great men reached and kept, Were not attained by sudden flight, They, whilst their companions slept, Were toiling upwards in the night....
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puneet (3514)

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hii

well u can ask only one question ... neways .. most of the answers are already there .. lemme tell something more about the 2nd question ... the vector (b*c) is not in the plane of b and c .. infact perpendicular to that plain ...

now, since the dot product of a with (b*c) is zero .. a must be in plain of b and c

and hence the answer

cheers


Puneet Agrawal
IIT Delhi
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