IIT JEE , AIEEE Forum - Mathematics , Vectors

Mr.IITIAN007

What is the locus of a point equidistant from 3 points whose position vectors

are a,b,c where r is the position vector of the given point?(NOTE:There is a vector arrow over a,b,c and r.)

puneet

hii

see the question in terms of normal goemetry .. the the point such that it is equi-distant from the two points lie on the perpendicular bisector ..

Now we want that point to be equidistant from the other (third) point also .. so there is a simple thing that there can be only such point and that point will be the circumcenter of the triangle formed by three points ..

I hope this is clear ..

cheers

Mr.IITIAN007

Can you give the vectorial expression for that circumcentre????

dhanuj

A point equidistant from 3 points will be the circumcentre of the triangle with these points as vertices.

_ _ _

Vectorial representation of circumcentre of triangle whose p.v's are a, b and c

will be

_ _ _ _ _ _

Ir-aI = Ir-bI = Ir-cI

Is it right??????????????????????????????????????????????????????????

Mr.IITIAN007

Can you explain it more clearly?????????????????????????????????????????????????????????????????????

nigitha_17

if OX=x n OY= y then XY=y-x.

since u said that that a,b,c r the pv's of three vertices of triangle n 'r' is the pv of req point that is equidistant from three given points AR=BR=CR if A,B,C ,R r considered the points for ur convienence

implies r-a=r-b=r-c.

if u stil dint follow u can ask which part u dint

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